This IIT JEE quiz would help you prepare well for Physics syllabus of CBSE 11 and 12
RI (γ-1)
PV
PV I (γ-1)
γρV I(γ-1)
(k1T1d2+ k2T2d1 ) / ( k1d2+ k2d1)
(k1T1+ k2d2 ) / ( d1+ d2)
[(k1d1+ k2d2 ) / (T1+ T2)] * T1T2
(k1d1T1+ k2d2T2 ) / ( k1d1+ k2d2)
E=(3/4) * (mv^2/qa)
Rate of work done by the electric field at P is (3/4) * (mv^3/a)
Rate of work done by the electric field at P is zero.
Rate of work done by both the fields at Q is zero.
αs/ αa
αa/ αs
αs/( αa + αs)
αa/( αa + αs)
One must use an ideal gas
Such a process is impossible
A change of phase is essential
One may use any real gas such as N2.
E1=E2
E2=2E1
E2=4E1
E2=16E1
0.13 m/s
0.18 m/s
3.7 m/s
5.2 m/s
Remain un-shifted.
Shift downwards by nearly two fringes.
Shift upward by nearly two fringes.
Shift downward by 10 fringes.
B*[(u – f) / f]½
B*[f /(u – f)] ½
B*[(u – f)/f]
B*[f / (u – f)]^2
1.25 cm
2.5 cm
1.05 cm
2 cm